1. A 0.20 kg glider moving at 5 m/s to the rightcollides with a 0.25 kg glider m
ID: 1724096 • Letter: 1
Question
1. A 0.20 kg glider moving at 5 m/s to the rightcollides with a 0.25 kg glider moving 2 m/s to the left. Afterwards, the0.25 kg glider moves 2 m/s to the right and the 0.20 kgglider moves 5 m/s to theleft.a. What was the initial momentum of the systemof two gliders? b. What was the final (after collision) momentumof the two gliders? c. What was the initial kinetic energy of thesystem of two gliders? d. What was the final kinetic energy of thesystem of two gliders? e. What quantity, if either, was conserved inthis collision? 1. A 0.20 kg glider moving at 5 m/s to the rightcollides with a 0.25 kg glider moving 2 m/s to the left. Afterwards, the0.25 kg glider moves 2 m/s to the right and the 0.20 kgglider moves 5 m/s to theleft.
a. What was the initial momentum of the systemof two gliders? b. What was the final (after collision) momentumof the two gliders? c. What was the initial kinetic energy of thesystem of two gliders? d. What was the final kinetic energy of thesystem of two gliders? e. What quantity, if either, was conserved inthis collision?
Explanation / Answer
Given : . m1 = 0.20 kg ; u1= 5 m /s ; v1 = - 5 m/s ( left ) . m2 = 0.25 kg ; u2= - 2 m /s (left) ; v2 = 2 m /s . (a) Initial momentum is : . m1 u1 + m2 u2 = ( 0.20 * 5 m /s) + (0.25 * - 2 m /s ) = 0.5 kg - m / s . (b) Final momentum is : . m1 v1 + m2 v2 = ( 0.20 * - 5 m /s ) + (0.25 * 2 m /s ) = - 0.5 kg - m /s . (c) Initial K.E is : . 1 /2 m1(u1)2 + 1/2 m2 (u2)2 = (0.5 *0.20 * 25 m /s) + (0.5 * 0.25 * 4 m /s ) . = ----------- J . (d) Final K.E is : . 1 /2 m1(v1)2 + 1/2 m2 (v2)2 = (0.5 *0.20 * 25 m /s) + (0.5 * 0.25 * 4 m /s ) . = ----------- J . (e) In this collision both momentum and Kinetic energyare conserved. . Hope this helps u! . = ----------- J . (e) In this collision both momentum and Kinetic energyare conserved. . Hope this helps u!Related Questions
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