Enter anumber. Enter a number. Enter anumber. Solution Resonance angular frequen
ID: 1724229 • Letter: E
Question
Enter anumber. Enter a number. Enter anumber.Explanation / Answer
Resonance angular frequency 0 = 1 / (L *C) = 1 / (3.00 * 2.00 *10-6) = 408.25 rad/s Power P = (Vrms2 / Z) * cos Impedance Z = {R2 + (XL - XC)2} power factor cos = R /Z a. At resonance XL = XC => Z = R cos = 1 Presonance = (1202 / 20.0) * 1 = 720.0 W b. 1/2 = 0 / 2 = 408.25 / 2 = 204.12 rad/s XL = * L = 204.12 * 3.00 = 612.37 XC = 1 / * C = 1 / 204.12 * 2.0 *10-6 = 2449.54 Z1/2 = {20.02 + (612.37 - 2449.54)2} = 1837.28 cos = R /Z1/2 = 20.0 / 1837.28 = 0.011 P1/2 = (1202 /1837.28) * 0.011 = 0.0862 W c. 1/4 = 0 / 4 = 408.25 /4 = 102.06 rad/s XL = * L = 102.06 * 3.00 = 306.18 XC = 1 / * C = 1 / 102.06 * 2.0 *10-6 = 4899.08 Z1/2 = {20.02 + (306.18 - 4899.08)2} = 4592.94 cos = R /Z1/2 = 20.0 / 4592.94 = 0.0043 P1/2 = (1202 /4592.94) * 0.0043 = 0.0136 W
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