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Enter anumber. Enter a number. Enter anumber. Solution Resonance angular frequen

ID: 1724229 • Letter: E

Question

Enter anumber. Enter a number. Enter anumber.

Explanation / Answer

   Resonance angular frequency   0   =   1 / (L *C)   =   1 / (3.00 * 2.00 *10-6) = 408.25   rad/s Power     P  =    (Vrms2 / Z) * cos Impedance Z = {R2 + (XL - XC)2}   power factor    cos = R /Z a. At resonance    XL   =  XC    =>   Z   =   R       cos = 1     Presonance =  (1202 / 20.0) * 1   =   720.0 W b.   1/2   =  0 / 2 = 408.25 / 2 = 204.12   rad/s     XL = * L = 204.12 * 3.00   =   612.37     XC   =   1 / * C   =   1 / 204.12 * 2.0 *10-6   =   2449.54       Z1/2   =  {20.02 +  (612.37 - 2449.54)2}  =   1837.28      cos =   R /Z1/2 =   20.0 / 1837.28  =   0.011     P1/2 =   (1202 /1837.28) * 0.011   =   0.0862   W c.   1/4 =  0 / 4 = 408.25 /4 = 102.06 rad/s     XL = * L = 102.06 * 3.00   =   306.18     XC   =   1 / * C   =   1 / 102.06 * 2.0 *10-6   =   4899.08     Z1/2   =  {20.02 +  (306.18 - 4899.08)2}   =  4592.94      cos =   R /Z1/2 =   20.0 / 4592.94 = 0.0043     P1/2 =   (1202 /4592.94) * 0.0043 =   0.0136 W