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A series circuit contains a 5.00/pi-H inductor, a 5.00/pi-Fcapacitor, and a 30.0

ID: 1724453 • Letter: A

Question

A series circuit contains a 5.00/pi-H inductor, a 5.00/pi-Fcapacitor, and a 30.0- resistor connected to a 120-V (rms)source of variable frequency. Find
a) the resonance frequency,    a. 10 hz b. 100 hz c. 1,000 hz d. 10,000 hz
b) the capacitive reactance [] at the resonancefrequency,    a. 10 b. 100 c. 1,000 d.10,000
c) the impedance [] at f=60hz,    a. Z<100 b. 100<Z<1,000 c.1,000<Z<10,000 d. 10,000<Z<100,000
d) the phase angle at f=60 hz,    a. -/2 < delta < -/4 b.-/4 < delta < 0 c. 0 < delta< /4 d. /4 < delta< /2
e) the power [W] delivered to the circuit at f=60 hz,    a. P < 1 b. 1 < P < 10 c. 10< P < 100 d. 100 < P < 1,000
((((I really need help with d and e. I already got the answersfor a-c which I think are right.))))
a) fo= 1/2LC    =1/(2(5.00/)(5.00/*10-6)) = 100 hz(b)
b) Kc= 1/2fC    =1/(2)(100hz)(5.00/*10-6) = 1,000 (c)
c) XL=2fL = 2(60)(5.00/) = 600    XC= 1/2fC =1/(2)(60)(5.00/*10-6) = 1667    Z = R2 + (XL - XC)2= 302 + (600-1667)2 = 1067 (c)

a) the resonance frequency,    a. 10 hz b. 100 hz c. 1,000 hz d. 10,000 hz
b) the capacitive reactance [] at the resonancefrequency,    a. 10 b. 100 c. 1,000 d.10,000
c) the impedance [] at f=60hz,    a. Z<100 b. 100<Z<1,000 c.1,000<Z<10,000 d. 10,000<Z<100,000
d) the phase angle at f=60 hz,    a. -/2 < delta < -/4 b.-/4 < delta < 0 c. 0 < delta< /4 d. /4 < delta< /2
e) the power [W] delivered to the circuit at f=60 hz,    a. P < 1 b. 1 < P < 10 c. 10< P < 100 d. 100 < P < 1,000
((((I really need help with d and e. I already got the answersfor a-c which I think are right.))))
a) fo= 1/2LC    =1/(2(5.00/)(5.00/*10-6)) = 100 hz(b)
b) Kc= 1/2fC    =1/(2)(100hz)(5.00/*10-6) = 1,000 (c)
c) XL=2fL = 2(60)(5.00/) = 600    XC= 1/2fC =1/(2)(60)(5.00/*10-6) = 1667    Z = R2 + (XL - XC)2= 302 + (600-1667)2 = 1067 (c)

Explanation / Answer

a) The frequency of an LC circuit is given by f = 1/(2(LC)) = 1/(2(5/ *5/*10-6)) = 1/10*10-3 hz. = 100hz b)Xc=(1/(2fC)) = 1/(2*100*5/*10-6) =1000

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