In the \"before\" part of Fig. 9-60, car A (mass 970 kg)is stopped at a traffic
ID: 1725096 • Letter: I
Question
In the "before" part of Fig. 9-60, car A (mass 970 kg)is stopped at a traffic light when it is rear-ended by carB (mass 1500 kg). Both cars then slide with locked wheelsuntil the frictional force from the slick road (with a lowk of 0.20) stops them, at distancesdA = 8.8 m and dB = 6.8 m.What are the speeds of (a) car A and(b) car B at the start of the sliding,just after the collision? (c) Assuming that linearmomentum is conserved during the collision, find the speed of carB just before the collision.
Explanation / Answer
(a)
if f is the frictional force then from newtonssecond law of motion we get
f = m a
the frictional force is given by
f = k n
= k m g
the deccelration of each car will be
a = f / m
= k m g /m
= k g
if d is the stopping distance using the equation ofmotion we get the speed v of the car just after
the impact as
v2 = vo2 + 2 ad
as vo = 0
the speed of car A will be
v2 = 2 a d
vA = (2 a d)
= (2k g dA)
= ........ m /s
(b)
the speed of car B will be
vB = (2 a d)
= (2k g dB)
= ........ m /s
(c)
if we take that v is the speed of car B justbefore the impact then from the law of conservation of
linear momentum we get
v = [(mA vA) +(mB vB)] / mB
= ....... m / s
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