What is the kinetic energy of a 190 - kg satellite as itfollows a circular orbit

Question

What is the kinetic energy of a 190 - kg satellite as itfollows a circular orbit of radius 7.0 x 106 m aroundthe Earth? (Mass of Earth = 6.0 x 1024 kg, G = 6.7 x10-11 N . m2/kg2) A.) 7.0 x 1010 J B.) 5.5 x 109 J C.) 8.0 x 1010 J D.) 7.5 x 1010 J E.) 6.0 x 109 J What is the kinetic energy of a 190 - kg satellite as itfollows a circular orbit of radius 7.0 x 106 m aroundthe Earth? (Mass of Earth = 6.0 x 1024 kg, G = 6.7 x10-11 N . m2/kg2) A.) 7.0 x 1010 J B.) 5.5 x 109 J C.) 8.0 x 1010 J D.) 7.5 x 1010 J E.) 6.0 x 109 J

Explanation / Answer

Kinetic Energy is : .                   K.E = (1/2 ) mvo2     ; Where vo   = Orbitalvelocity . We have : vo   = GM/R   = ( 6.7 x 10-11 * 6.0 x1024 kg )/ 7.0 x 106 m .                                            =   7.578 * 103   m/s . Hence K.E =   0.5 * 190 * (7.578 * 103   )2 .                    =   5.455 * 109   J .                    =   5.5 * 109   J . Hope this helps u!

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