(c) What is its speed at x = 7.0 m? 5 m/s Solution m = 2.0 kg. at x =2.5 m, v =

Question

(c) What is its speed at x = 7.0 m?
5 m/s

Explanation / Answer

m = 2.0 kg. at x =2.5 m, v = -2.0 m/s. U = -10 J a) F(x) = -dU(x)/dx = -[(-17.2) - (-2.8)]/(4 - 1) = 4.8 N > 0,so positive direction b) total energy E = mv2/2 + U = 4.0 - 10 = -6.0 J Since kinetic energy mv2/2 = E - U(x) 0, thepotential energy U(x) E = -6.0 J,so at the limits U(x) = -6.0 J, from the graph, the equation of the line connecting (1, -2.8) and(4, -17.2) is U(x) = -4.8x + 2.0 when U(x) = -6.0, x = 1.67 m equation of the line connecting (8.5, -17.2) and (15, -2) is U(x) =2.34x - 37.1 when U(x) = -6.0, x = 13.3 m x = 1.67 m (lower limit) x = 13.3 m (upper limit) c) At x = 7.0 m, U = -17.2 J mv2/2 - 17.2 = -6 v = ±3.35 m/s

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.