The electric field of an electromagnetic wave is given by; E=4.45 x 10 2 sin(3.1

Question

The electric field of an electromagnetic wave is given by;
E=4.45 x 102sin(3.10 x 106*pi(x-3.0 x108*t))
where everything is in SI units. What is the wave'sfrequency? and,,, what is the amplitude of the magnetic field associated withthis TEM (transverse electromagnetic) wave?
The electric field of an electromagnetic wave is given by;
E=4.45 x 102sin(3.10 x 106*pi(x-3.0 x108*t))
where everything is in SI units. What is the wave'sfrequency? and,,, what is the amplitude of the magnetic field associated withthis TEM (transverse electromagnetic) wave?

Explanation / Answer

    E = 4.45 X 10 2 sin [ 3.1 X 106 * ( x - 3 X 10 8 t ) ]        = 445 sin ( 3.1 X 106 x - 9.3 X 10 14 t ) ....................(1)     General equation of E is     E = Eo sin ( k x - t ).................................(2)     where Eo = Amplitude                 = angular frequency     By comparing (1) and (2)     Angular frequency, = 9.3 X 1014     Frequency, f = / 2                        = 4.65 X 10 14 Hz     Amplitude of E , Eo = 445 N/C

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