A mass, m, hangs vertically from a spring. When additionalmass is attrached, the

Question

A mass, m, hangs vertically from a spring. When additionalmass is attrached, the total mass supported by the spring equals0.20 kg, and the spring elongates so that the mass m is at adistance of 9.50 cm below the support point of the spring. Addingan additional 800 grams brings the total ass supported by thespring to 1.00 kg. This stretchs the spring an additional 2.50 cm.Calculate the spring constant k in Newtons per centimeter(N/cm). I got this question wrong on my homework. i really have noidea how to do this at all. Can someone please help me. A mass, m, hangs vertically from a spring. When additionalmass is attrached, the total mass supported by the spring equals0.20 kg, and the spring elongates so that the mass m is at adistance of 9.50 cm below the support point of the spring. Addingan additional 800 grams brings the total ass supported by thespring to 1.00 kg. This stretchs the spring an additional 2.50 cm.Calculate the spring constant k in Newtons per centimeter(N/cm). I got this question wrong on my homework. i really have noidea how to do this at all. Can someone please help me.

Explanation / Answer

we know that F = kx so mg = kx therefore k = mg/x = (0.8kg) (9.8m/s2 ) / (2.5cm) = 3.13 N/cm

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