presents a model for solving this problem. A solid concrete blockweighs 190 N an

Question

presents a model for solving this problem. A solid concrete blockweighs 190 N and is resting on the ground. Its dimensions are 0.410m x 0.170 m x 0.0840 m. A number of identical blocks are stacked ontop of this one. What is the smallest number of whole bricks(including the one on the ground) that can be stacked so that theirweight creates a pressure of at least two atmospheres on the groundbeneath the first block? (Hint: First decide which face of thebrick is in contact with the ground.) Number Units No unitsskgmm/sNN·mJPa Number Units No unitsskgmm/sNN·mJPa

Explanation / Answer

    the pressure exerted by N blocks stacked on topof one another is     P = F / A        = N Wone block /A     where Wone block is weight of oneblock     the least number of whole blocks required toproduce a pressure of two atmospheres (2.02 x 105 Pa)is     N = P A / Wone block         = (2.02 x 105Pa) (0.170 m x 0.0840 m) / 190 N         = ........

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