Two loudspeakers placed 6.0 m apart are driven in phase by anaudio oscillator, t

Question

Two loudspeakers placed 6.0 m apart are driven in phase by anaudio oscillator, that has a frequency range from 500 Hz to 700Hz. A point P is located 2.5 m from one loudspeaker and 3.5 mfrom the other. The speed of sound in air is 344 m/s. A. What frequency would you tune the oscillator to get maximumconstructive interference at point P? B. What frequency would you tune the oscillator to get maximumdestructive interference at point P? Two loudspeakers placed 6.0 m apart are driven in phase by anaudio oscillator, that has a frequency range from 500 Hz to 700Hz. A point P is located 2.5 m from one loudspeaker and 3.5 mfrom the other. The speed of sound in air is 344 m/s. A. What frequency would you tune the oscillator to get maximumconstructive interference at point P? B. What frequency would you tune the oscillator to get maximumdestructive interference at point P? A. What frequency would you tune the oscillator to get maximumconstructive interference at point P? B. What frequency would you tune the oscillator to get maximumdestructive interference at point P?

Explanation / Answer

n = 2.5 (n + m) = 3.5       wheren and m are integers - distance to each speaker is anintegral number of wavelengths m = 1       subtractingequations m v / f = 1       f = m v = 2 *344 = 688 / sec     for constructiveinterference       2.5 = n 3.5 = (n + m) + / 2 1 = m + / 2 = (m + 1/2) = (m + 1/2) v /f f = (m + 1/2) v = 3/2 * 344 = 516 / sec for destructiveinterference

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.