Two children hang by their hands from the same tree branch. Thebranch is straigh

Question

Two children hang by their hands from the same tree branch. Thebranch is straight, and grows out from the tree trunk at an angleof 28.7° above the horizontal. Onechild, with a mass of 47.6 kg, is hanging1.31 m along the branch from the treetrunk. The other child, with a mass of 33.3 kg, is hanging 2.19 mfrom the tree trunk. What is the magnitude of the net torqueexerted on the branch by the children? Assume that the axis islocated where the branch joins the tree trunk and is perpendicularto the plane formed by the branch and the trunk.
1 N · m

Explanation / Answer

Given
distance to line of force for F1 is 2.19m distance to line of force for F2 is 1.31cos(28.7)=-1.19

Torque by a force=(distance to line of action by theforce)(force) distance to line of force for F2 is 1.31cos(28.7)=-1.19 F1=33.3g=326N F2=47.6g=466N =326*(2.19)+466*(-1.19)=159.4Nm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.