A 0.2 kg plastic cart and a 20 kg lead cart can both rollwithout friction on a h

Question

A 0.2 kg plastic cart and a 20 kg lead cart can both rollwithout friction on a horizontal surface. Equal forces are used topush both carts forward for a time of 1 s, starting from rest.After the force is removed at t=1 s, is the momentum of the plasticcart greater than, less than or equal to the momentum of the leadcart? Explain.

Explanation / Answer

Given: Momentum = m*v F = m*a v=a*t So, if we use the formulas, we find that a = F/m => a1 =F/m1        a2 = F/m2 v1 = a1*t =F*t/m1             v2 = a2*t = F*t/m2 momentum: m1*v1 =F*t*m1/m1 =F*t                   m2*v2 = F*t*m2/m2 =F*t So both of them are equal to the force times the time, which meansthat the momenta of the carts are equal.

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