A 60 g ball is tied to the end of a 50 cm long string and swung ina vertical cir

Question

A 60 g ball is tied to the end of a 50 cm long string and swung ina vertical circle. The center of the circle, as shown in the figure, is 150 cm above the floor. The ball is swung at the minimumspeed necessary to make it over the top without the string goingslack. If the string is released at the instant theball is at the top of the loop, how far to the right does the ballhit the ground? Express your answer using twosignificant figures. If the string is released at the instant theball is at the top of the loop, how far to the right does the ballhit the ground? Express your answer using twosignificant figures.

Explanation / Answer

Radius  ( r ) = 50 cm = 0.5 m Mass ( m ) = 60 kg g = 9.8 m/s2 minimum speed necessary to make it over the top without thestring going slack    v = [ rg ]       = (0.5m ) ( 9.8m/s2)       = 2.213 m / s Height ( H ) = 150 cm = 1.5 m distance of the ball when ti hits the ground S = vt where t = time taken to reach the ground fro top             = [ 2H / g ]             = 0.5532 s S = v * t = 2.213 m / s * 0.5532 s          = 1.2244m I hope it helps you

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