A cylinder 0.150m in diameter rotates in a lathe at 620rpm.What is the tangentia

Question

A cylinder 0.150m in diameter rotates in a lathe at 620rpm.What is the tangential speed of the surface of the cylinder? The proper tangential speed for machining cast iron is about0.600m/s. At how many revolutions per minute should a piece ofstock 8.00×102meters in diameter berotated in a lathe to produce this tangential speed? A cylinder 0.150m in diameter rotates in a lathe at 620rpm.What is the tangential speed of the surface of the cylinder? The proper tangential speed for machining cast iron is about0.600m/s. At how many revolutions per minute should a piece ofstock 8.00×102meters in diameter berotated in a lathe to produce this tangential speed?

Explanation / Answer

   Given that the diameter of cylinder is d = 0.150 m    Initial angular velocity is = 620 rev/min =64.89 rad/s ------------------------------------------------------------- Then the radius of cylinder is r = d/2 = 0.075 m Then the tangential speed is v = r                                           = (0.075m)(64.89 rad/s)                                             = 4.86 m/s ------------------------------------------------------------------------------------------------ Tangential speed is v = 0.600 m/s Diameter is d = 8.00*10-2 m radius is r = d/2 = 4.00*10-2 m Then the angular velocity is = v / r                                               = 15 rad/s          =143.31 rev/min

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