(a) At what value of y p dothe rays have the minimum possible phase (path length

Question

(a) At what value of yp dothe rays have the minimum possible phase (path length)difference?
1

(b) What multiple of gives that minimum phasedifference?
2

(c) At what value of yp do the rays have themaximum possible phase difference?
3

(d) What multiple of gives that maximum phasedifference?
4

(e) What multiple of gives the phase difference whenyp = d?
5

(f) When yp = d, is the resultingintensity at point P maximum, minimum, intermediate butcloser to maximum, or intermediate but closer to minimum?
6
I don't even know where to begin!! Thanks!!

Explanation / Answer

(a)
    the minimum path length difference occurs whenboth rays are nearly vertical this would correspond to a point asfar up

    in the picture as possible
    treating the screen as if it extended foreverthen the point is at y =
(b)
    when both the rays are nearly vertical there isno path length difference between them thus at y = thephase
    difference is zero
(c)
    at y = 0 both rays are horizontal with the rayfrom S1 being longer than one from S2 bydistance d
(d)
    as d = 6.00
    then the phase difference here is = 6.20wavelengths and is at its maximum value
(e)
    = (L1 - L2) /

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