(a) What is the coefficient of static friction between the trackand the car\'s t
ID: 1727360 • Letter: #
Question
(a) What is the coefficient of static friction between the trackand the car's tires? (b) What would be the maximum speed if no downforce acted on thecar? 22. An 830-kg race car can drive around an unbanked turn at amaximum speed of 58 m/s without slipping. The turn has a radius ofcurvature of 160 m. Air flowing over the car's wing exerts adownward-pointing force (called the downforce) of 11 000 N on thecar. (a) What is the coefficient of static friction between the trackand the car's tires? (b) What would be the maximum speed if no downforce acted on thecar?Explanation / Answer
Mass of the car, M = 830 kg Velocity of the car, V = 58 m/s Radius of curvature, R = 160 m Downward force, F = 11000 N (a) Total force in downward direction on the car, F' = M g + F = ( 830 * 9.8 ) + 11000 = 19134 N Normal force, N = F ' = 19134 N Frictional force, f = N ( where =coefficient of friction ) During circular motion, Frictional force = Centripetal force N = M V 2 / R * 19134 = ( 830 * 58 2 ) /160 Coefficient of friction, = 0.9 (b) Normal force , N = M g Frictional force, f = N = M g During circular motion, Centripetal force = Frictional force M V 2 / R = M g Velocity, V = ( R g ) = ( 0.9 * 160 * 9.8 ) = 37.8 m/s
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