The motor of a table saw is rotating 3450 rev/min. A pulleyattached to the motor

Question

The motor of a table saw is rotating 3450 rev/min. A pulleyattached to the motor shaft drives drives a second puller of halfthe diameter by means of a V-belt. A circular saw bladeof diameter 0.208 m is mounted on the same rotating shaft as thesecond pulley.

a.) The operator is careless and the blade catches and throws backa small piece of wood. This piece of wood moves with a linearspeed equal to the tangential speed of the rim of the blade. What is this speed?

b.) Calculate the radial acceleration of points on the outer edgeof the blade to see why sawdust doesn't stick to its teeth.

Explanation / Answer

3450/.5=6900 RPM 6900 RPM * 2pi = 43332 radians/min = angular velocity 1) tangential speed = angular velocity*radius of blade 2) radial acceleration of points = tangential speed^2/radius ofblade This is all I know. I hope this helps.

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