Object A is moving due east, while object B is moving duenorth. They collide and
ID: 1727435 • Letter: O
Question
Object A is moving due east, while object B is moving duenorth. They collide and stick together in a completely inelasticcollision. Momentum is conserved. Object A has a mass ofmA = 17.2 kg and an initial velocity ofv0A = 7.42m/s, due east. Object B, however, has a mass ofmB = 29.7 kg and an initial velocity ofv0B = 5.28m/s, due north. Find the (a) magnitude and(b) direction of the total momentum of thetwo-object system after the collision. the answer isnt necessarily needed- i just need to know how toarrive there. Thanks! Object A is moving due east, while object B is moving duenorth. They collide and stick together in a completely inelasticcollision. Momentum is conserved. Object A has a mass ofmA = 17.2 kg and an initial velocity ofv0A = 7.42m/s, due east. Object B, however, has a mass ofmB = 29.7 kg and an initial velocity ofv0B = 5.28m/s, due north. Find the (a) magnitude and(b) direction of the total momentum of thetwo-object system after the collision. the answer isnt necessarily needed- i just need to know how toarrive there. Thanks!Explanation / Answer
. Object A is moving due east, . Object A has a mass of mA =17.2 kg and an initial velocity of v0A =( 7.42 m/s ) i . Object B is moving due north . Object B, however, has a mass of mB =29.7 kg and an initial velocity ofv0B =( 5.28 m/s ) j . From the conservation of momentum . m1 v0A + m2 v0B = ( m1 + m2 ) V . or 17.2 * 7.42 i + 29.7 * 5.28 j = ( 17.2 + 29.7 ) V . or 2.72 i + 3.34 j = V . Hence Magnitude is : . V = ( 2.72)2 + (3.34)2 = 4.30 m /s . Direction is : . = tan-1 ( 3.34 /2.72 ) = ---------- degree . Solve it . Hope this helps u!Related Questions
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