A 200 gram block, attached to the end of an ideal spring(horizontal) with force

Question

A 200 gram block, attached to the end of an ideal spring(horizontal) with force constant k = 70 N/m, undergoes simpleharmonic motion with a maximum displacement of 5.0 cm from therelaxed position. Ignore any friction or air resistance.
Compute the amplitude of oscillations. Compute the maximum speed of the block. At which position is the velocity of the block is themaximum? Compute the magnitude of the maximum acceleration of theblock.
Compute the amplitude of oscillations. Compute the maximum speed of the block. At which position is the velocity of the block is themaximum? Compute the magnitude of the maximum acceleration of theblock.

Explanation / Answer

Amplitude of oscillations A = 5 cm                                           =0.05 m Force constant k = 70 N / m mass m = 200 g = 0.2 kg maximum speed V = A w                             = A [ k / m ]                             = 0.9354 m / s Velocity is maximim at equilibrium position Maximum accleration a= Aw ^ 2                                   = A ( k / m)                                   = 17.5 m / s ^ 2

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