A box weighing 131 lb is in free fall. Howmuch force is the box exerting on Eart
ID: 1728592 • Letter: A
Question
A box weighing 131 lb is in free fall. Howmuch force is the box exerting on Earth and in what direction?1 lb
In which of the followingsituations will a torque be present? Choose all that apply.
1 A sphere is spinning with a constantangular velocity. A 369 N forceis applied at the axis of rotation. A rotatingbody has an angular acceleration of 66rad/s2. A 3181 N forceis applied 54 cm from the axis of rotationand is parallel to the lever arm. A force isapplied 71 cm away from the axis ofrotation and is perpendicular to the lever arm.
In which of the followingsituations will a torque be present? Choose all that apply.
1 A sphere is spinning with a constantangular velocity. A 369 N forceis applied at the axis of rotation. A rotatingbody has an angular acceleration of 66rad/s2. A 3181 N forceis applied 54 cm from the axis of rotationand is parallel to the lever arm. A force isapplied 71 cm away from the axis ofrotation and is perpendicular to the lever arm.
1 A sphere is spinning with a constantangular velocity. A 369 N forceis applied at the axis of rotation. A rotatingbody has an angular acceleration of 66rad/s2. A 3181 N forceis applied 54 cm from the axis of rotationand is parallel to the lever arm. A force isapplied 71 cm away from the axis ofrotation and is perpendicular to the lever arm. 1 A sphere is spinning with a constantangular velocity. A 369 N forceis applied at the axis of rotation. A rotatingbody has an angular acceleration of 66rad/s2. A 3181 N forceis applied 54 cm from the axis of rotationand is parallel to the lever arm. A force isapplied 71 cm away from the axis ofrotation and is perpendicular to the lever arm. 1
Explanation / Answer
Mass of the box, M = 131 lb = 131 * 0.4536 kg = 59.43 kg Force exerted by the box on the earth, F = Mg = 59.43 * 9.8 = 582.3 N ( upward ) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Torque, = Moment of inertia * Angularacceleration = I ( O R ) Torque, = Force * Perpendiculardistance of line of action of force from the axis ofrotation = F * d Ans : ( i ) A rotating body has an angularacceleration of 66 rad/s2 (ii ) A force is applied 71 cm away fromthe axis of rotation and is perpendicular to the lever arm
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.