A satellite moves in a circular orbit around Earth at a speedof 5478 m/s. (a) De

Question

A satellite moves in a circular orbit around Earth at a speedof 5478 m/s. (a) Determine the satellite's altitude abovethe surface of Earth.
1 m
(b) Determine the period of the satellite's orbit.
2 h    N/bPlease partial solutions will not help me; solve to the finnish notjust formulars. (a) Determine the satellite's altitude abovethe surface of Earth.
1 m
(b) Determine the period of the satellite's orbit.
2 h    N/bPlease partial solutions will not help me; solve to the finnish notjust formulars.

Explanation / Answer

Speed v = 5478 m / s (a). we know v = [ GM / ( R + h )]             R+h= GM / v ^ 2         ----(1) where G = Gravitational constant = 6.67* 10^-11 N m ^2/kg^2           M =Mass of earth = 5.98 * 10 ^ 24 kg            R= Radius of earth = 6.38 * 10 ^ 6 m plug the values weget R+h = 1.3291* 10 ^ 7 m                                          = 13.291* 10 ^ 6 m the satellite's altitude above the surface of Earth h = (13.291*10^6 ) - R                                                                            =6.911* 10^6 m (b). the period of the satellite's orbit T = 2(R+h) /v                                                          = 1.5244 * 10^4 s                                                          = ( 1.5244*10^4 ) / 3600                                                          = 4.234 h

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