Hello, I have got a question about an exercice in physics.(chapter19, 12P) You h

Question

Hello,
I have got a question about an exercice in physics.(chapter19, 12P) You have to find how many electrons there are in a systemwith 1525 particles, but I wonder whether you can also calculatethis for the protons seperately? The answer that was given hereis:
Q = Np . e - Ne . e => Ne = 1/2 [ 1525 - Q/e] and you know thatQ= -5.456.10^-17 . Can anyone give me some more information about thisexercice?

I have got a question about an exercice in physics.(chapter19, 12P) You have to find how many electrons there are in a systemwith 1525 particles, but I wonder whether you can also calculatethis for the protons seperately? The answer that was given hereis:
Q = Np . e - Ne . e => Ne = 1/2 [ 1525 - Q/e] and you know thatQ= -5.456.10^-17 . Can anyone give me some more information about thisexercice?

Explanation / Answer

Number of particles in the system Np +Ne = 1525 charge on electron e = -1.6*10-19C charge on proton    ep =1.6*10-19 C Net charge of the system Qnet = -5.456*10-17C                          Qnet = Np e - Nee                                   = e ( Np - Ne )                                    = e ( 1525 -  Ne - Ne )                                      =e ( 1525 -2Ne )      Ne = 1/2 ( 1525 -(  - 5.456*10-17C / 1.6*10-19C ) )            = 933     b ) Total mass of the systemMtotal = Np mp +Ne me                                                         = ( 1525 - 933 ) ( 1.673*10-27 kg ) + (933 ) (9.11*10-31 kg )                                                      = 9.91*10-25 kg                                                         = ( 1525 - 933 ) ( 1.673*10-27 kg ) + (933 ) (9.11*10-31 kg )                                                      = 9.91*10-25 kg

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.