A mass M 1 is attached to a support by astring of length l=0.5m and released fro

Question

A mass M1 is attached to a support by astring of length l=0.5m and released from rest when it makes anangle o=60 degrees with the vertical. At itslowest point it collides elastically with a mass M2sitting on a frictionless table. M1=1kg andM2=2kg. What is the speed of M1 just beforethe collision? What is the speed of M1 just after thecollision? A mass M1 is attached to a support by astring of length l=0.5m and released from rest when it makes anangle o=60 degrees with the vertical. At itslowest point it collides elastically with a mass M2sitting on a frictionless table. M1=1kg andM2=2kg. What is the speed of M1 just beforethe collision? What is the speed of M1 just after thecollision?

Explanation / Answer

   From law of conservation of energy   mgh = 1/2 mv2    therefore v = (2gh)= (2*9.8) L(1-cos)          = (2*9.8) (0.5) (1-cos60) = 2.2 m/s From law of conservation of momentum    the final velocity    vf =[ (m1 - m2) /(m1 + m2) ]vi =[ ( 1 -2) / (1+ 2) ](2.2) = 0.73m/s    therefore v = (2gh)= (2*9.8) L(1-cos)          = (2*9.8) (0.5) (1-cos60) = 2.2 m/s From law of conservation of momentum    the final velocity    vf =[ (m1 - m2) /(m1 + m2) ]vi =[ ( 1 -2) / (1+ 2) ](2.2) = 0.73m/s

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