Nasa lands a 10kg space probe on planet Zero (mass of5.0x10 23 kg, radius of 3.0
ID: 1729177 • Letter: N
Question
Nasa lands a 10kg space probe on planet Zero (mass of5.0x1023kg, radius of 3.0x106m, noatmosphere). (A) If the probe is to acheive a maximum distance of2.0x106m from the SURFACE of Zero, with what initialspeed must it be launched directly upward from the surface ofZero? (B) In a separate situation, supposed the probe moves in acircular orbit about Zero with radius 5.0x106m. Nasawishes to move the probe to a new circular orbit of radius4.0x106m by executing a series of thruster burns. Forhow many total seconds must the thrusters burn if they produce100kW of power? [hint: remember that power*time - energy and for acircular orbit Emech = -KE = 1/2Ugrav] Thanks for your help! Nasa lands a 10kg space probe on planet Zero (mass of5.0x1023kg, radius of 3.0x106m, noatmosphere). (A) If the probe is to acheive a maximum distance of2.0x106m from the SURFACE of Zero, with what initialspeed must it be launched directly upward from the surface ofZero? (B) In a separate situation, supposed the probe moves in acircular orbit about Zero with radius 5.0x106m. Nasawishes to move the probe to a new circular orbit of radius4.0x106m by executing a series of thruster burns. Forhow many total seconds must the thrusters burn if they produce100kW of power? [hint: remember that power*time - energy and for acircular orbit Emech = -KE = 1/2Ugrav] Thanks for your help!Explanation / Answer
(a) conservation of energy... . initial K + U = final K + U . (1/2) mv2 - G M m / R = 0 - G M m /r . v2 = 2GM/R - 2GM/r = 2GM (r -R) / rR = . = 2 * 6.673 x 10-11 * 5.0 x 1023(2.0 x 106 ) / (5.0 x 106 ) (3.0 x106) = . = 8.8973 x106 but... v is the sq root of this or . v = 2983 m/s .Related Questions
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