A 1.5 kg block slides across a surface, hits a spring with aspeed of 5.7 meters/

Question

A 1.5 kg block slides across a surface, hits a spring with aspeed of 5.7 meters/second. If the spring has a spring constant ofk = 500 Newtons/meter, and it is compressed by 0.3 meters, what canbe concluded about the surface: a) if the surface is horizontal b) if the surface is frictionless A 1.5 kg block slides across a surface, hits a spring with aspeed of 5.7 meters/second. If the spring has a spring constant ofk = 500 Newtons/meter, and it is compressed by 0.3 meters, what canbe concluded about the surface: a) if the surface is horizontal b) if the surface is frictionless

Explanation / Answer

it is given that the spring iscompressed to 0.3m. so gain in spring potential energy=1/2kx2=1/2*500*0.32=22.5J. as the block is come at rest loss in kinetic energy=1/2mv2=1/2*1.5*5.72=24.367N. as the loss in kinetic energy is more than gain in spring potentialenergy a)the surface must be frictional one. b)the surface is inclined and the spring s at the bottom of thesurface.

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