A piece of concrete measures 3 ft by 3 ft by 1.25 ft. (a) Whatis its weight? (b)

Question

A piece of concrete measures 3 ft by 3 ft by 1.25 ft. (a) Whatis its weight? (b) Find the buoyant force that acts on it when it issubmerged in water. (c) What is the net force on the concrete piece when it isunder water? Please work the problem out in detail, so I can understandit. Worth 14 Thank you. A piece of concrete measures 3 ft by 3 ft by 1.25 ft. (a) Whatis its weight? (b) Find the buoyant force that acts on it when it issubmerged in water. (c) What is the net force on the concrete piece when it isunder water? Please work the problem out in detail, so I can understandit. Worth 14 Thank you.

Explanation / Answer

      1 ft = 0.3048 m      volume of the concrete V = 3ft * 3ft * 1.25 ft                                             = ( 3 * 0.3048m)(3*0.3048m) (1.25*0.3048)                                             = 0.31 m3     density ofconcrete         = 2400 kg/ m3      mass   ofconcrete    m =   * V                                          = 2400 * 0.331                                           = 764 kg    Weight of the concrete W =mg                                            = 764 * 9.8                                            = 7492 N      buoyancy force F =Vg                                  = 1000 * 0.31 * 9.8                                   = 3038 N    

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