Flexure Test of Concrete Beam Width of Beam (b) 6incheHeight of Beam (h)- 5 inch

Question

Flexure Test of Concrete Beam Width of Beam (b) 6incheHeight of Beam (h)- 5 inches d Area of Steel (A 22 suare inchesYield Strength of Steel (F,) 60,000 psi Calculated value of (a) Theoretical ultimate moment (M) Distance between beam supports 27.l inches Ultimate load applied to beam 10.090 lbs Actual ultimate moment on beam Ultimate Outer Fiber Compressive Stress Modulus of elasticity Deflection Deflection 0021 0029 0035 0039 6500 500 1000 1500 2000 2500 3000 3500 4000 4500 5000 7500 8000 8500 9000 9500 10000 10090 0106 0114 0122 0132 0148 0163 0049 0054 0059 0065 Not Measured 5500 6000 .0085

Explanation / Answer

ANS:

Sol- a) To calculated d, assume clear cover of 30mm and substracting bar diameter take nominal cover as 50 mm.

d = 127 - 50 = 77 mm.

b) Mur = fy * Ast * ( d - .42Xu,max)

Xu,max = .48*d = .48*77 = 36.96 mm

Mur = 415*14195*(77 - .42*36.96)

= 362.155 KN-m

c) Actual Mur for simply supported beam is PL^2/4.

Mur = 44.883*.688^2 / 4 = 5.31127 KN-m

d) We know M/I = f/y

Using actual Mur to determine outer fibre stress and Moment of inertia I = bd^3 / 12 = 1024191.5 mm^4. Y is equal to Xu,max.

f = 5.311 * 10^6 * 36.96 / 1024191.5 = 191.658 N/mm^2

All calculations are done in SI units.

PLEASE RATE THUMBSUP GUYS

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