Hello, I\'m trying to understand how they got the angle. This phasor concept has

Question

Hello, I'm trying to understand how they got the angle. This phasor concept has got me confused.
In this case, V1 RMS = 2.061 and V2 RMS = 1.146. How did they get 52.4 degrees? I've submitted the part where I am confused.

LAB REPORT (Weight: 60%) Phasor relations (a)From the printout data of Step 3 , draw the voltage phasors Vi, V2 and the current phasor I on the complex co-ordinate plane below. Then draw the phasor Ip-VI/Rp .Graphically obtain Vc by using the KVL phasor relation Vc - Vi-V2.[Either draw the diagram to 'scale' or use complex-number algebra* on the phasors you have drawn.[* show calculations by the side of the diagram] C ,636V volts

Explanation / Answer

Let's assume that x is the angle between the V1 and V2. Since magnitude of V2 is greater than magnitude of V1, so we can write - V2 * Cos(x) = V1 => x = Cos-1(1.146/2.061) =   56.220 . The angle between V1 and V2 phasor is 56.220 only and not the 52.40 .

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