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17. -15 points SerPSE8 39.P.075. My NotesAsk Your Teache Owen and Dina are at re

ID: 1730632 • Letter: 1

Question

17. -15 points SerPSE8 39.P.075. My NotesAsk Your Teache Owen and Dina are at rest in frame S', which is moving at v0.560c with respect to frame S. They play a game of catch while Ed, at rest in frame S, watches the action (see figure below). Owen throws the ball to Dina at V2 = 0.760c (according to Owen), and their separation (measured in S') is equal to d 1.75 x 1012 m. Vi V2 0 Dina Ed (a) According to Dina, how fast is the ball moving? (b) According to Dina, what time interval is required for the ball to reach her? (c) According to Ed, how far apart are Owen and Dina. (d) According to Ed, how fast is the ball moving. (e) According to Ed, what time interval is required for the ball to reach Dina? Need Help?Read ItTalk to a Tutor

Explanation / Answer

a) applying concept of relative velocity

-0.76 c

b) time= distance/speed

t = 1.75*10^12/0.76*3*10^8 = 7675.438 s

c)

d = sqrt(1 -0.56^2) *1.75*10^12 = 1.45*10^12 m

d)

V= (-0.76 + 0.56)/(1 - 0.76*0.56) = - 0.3482 c

e).

Relative distance= (1-0.56^2)^0.5*1.75*10^12= 1.45*10^12

Relative speed= 0.56 - 0.3482 = 0.2118 c

t= 1.45*10^12/(0.2118*10^8*3)= 22820.27 s
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