(8%) Problem 5: The magnetic field of a proton is approximately like that of a c

Question

(8%) Problem 5: The magnetic field of a proton is approximately like that of a circular current loop 0650 x 10-15 m in radius carrying 1.05 x 104 A. An MRI machine needs to be able to manipulate these fields. 50% Part (a) To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400 loop-per- meter circular coil 0.660 m in radius to create a 1.20 T field (typical of an MRI instrument) at its center with no iron insert. > 50% Part (b) what is the field at the center of a proton? Notice how it compares to the field we used in the previous calculation. Grade Summary Potential 100%

Explanation / Answer

(A) B = u0 (N / L) I

1.20 T = (4pi x 10^-7) (400 turns/m) (I)

I = 2387 A ......Ans

(B) B = u0 I / (2 R )

B = (4pi x 10^-7) (1.05 x 10^4) / (2 x 0.650 x 10^-15)

B = 1.01 x 10^13 T

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