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session.masteringphysics.com Netflix ROKOtv I Ep Hours I Leddy Chegg Study direction of net f Copy of University Physics with Modern Physics Young/Freedman 14e KAssignment 3 Problem 24.53 5 of 11> Part A In the figure (Figure 1), Ci C5-8.3 F and C2-C3 4.4 AF. The applied potential is Vab 250 V C4 What is the equivalent capacitance of the network between points a and b? Express your answer using two significant figures. Submit Part B Figure 1 of Calculate the charge on capacitor C1 Express your answer using two significant figures. (a Request Answer Part C Calculate the potential diference across capacitor C Express your answer using two significant figuresExplanation / Answer
Remember:
For parallel combination
Ceq = C1 + C2 + C3 +...............
for series combination
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............
for 2 capacitors in series it will be
Ceq = C1*C2/(C1+C2)
Using this Information:
C3 and C4 are in series, & C3 = C4
C34 = 4.4/2 = 2.2 uF
C2 and C34 are in parallel, So
C234 = 2.2 + 4.4 = 6.6 uF
C1, C5 and C234 are in series, So
1/Ceq = 1/8.3 + 1/8.3 + 1/6.6
Ceq = (1/8.3 + 1/8.3 + 1/6.6)^-1
Ceq = 2.5 uF
Qeq = Ceq*V = 2.5*10^-6*250
Qeq = 6.3*10^-4 C
Now remember in capacitors parallel combination voltage distribution in each part will be same and in series combination charge distribution in each capacitor will be same.
Q1 = Q5 = Q234 = Qeq
Q1 = 6.3*10^-4 C
V1 = Q1/C1 = 6.3*10^-4/(8.3*10^-6) = 76 V
Q5 = 6.3*10^-4 C
V5 = Q5/C5 = 6.3*10^-4/(8.3*10^-6) = 76 V
Q234 = 6.3*10^-4 C
V234 = Q234/C234 = 6.3*10^-4/(6.6*10^-6) = 95 V
Since V2 and V34 are in parallel, So
V2 = V34 = V234
V2 = 95 V
Q2 = C2*V2 = 4.4*10^-6*95 = 4.2*10^-4 C
V34 = 95 V
Q34 = 2.2*10^-6*95 = 2.1*10^-4 C
Since Q3 and Q4 are in series, So
Q3 = Q4 = Q34
Q3 = 2.1*10^-4 C
V3 = Q3/C3 = 2.1*10^-4/(4.4*10^-6) = 48 V
Q4 = 2.1*10^-4 C
V4 = Q4/C4 = 2.1*10^-4/(4.4*10^-6) = 48 V
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