The cornea of the eye has a radius of curvature of approximately 0.48 cm , and t

Question

The cornea of the eye has a radius of curvature of approximately 0.48 cm , and the aqueous humor behind it has an index of refraction of 1.35. The thickness of the cornea itself is small enough that we shall neglect it. The depth of a typical human eye is around 25.0 mm .

What would have to be the radius of curvature of the cornea so that it alone would focus the image of a distant mountain on the retina, which is at the back of the eye opposite the cornea?

Express your answer using two significant figures.

Explanation / Answer

n2=1.35

n1= 1 (of air)

f = R/2= 0.48/2 = 0.24 cm

Now use R = f*(n2-n1)/n2 = 0.24*(1.35 - 1)/1.35 = 0.062 cm = 0.62 mm

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