The I north pole of a bar magnet is moved toward the center of the loop of coppe

Question

The I north pole of a bar magnet is moved toward the center of the loop of copper wire shown Choose the appropriate word choices below that correctly complete the blanks in the following four sentences: 1. The original B field from the bar maguet penetrating the loop points page 2. As the north pole of the bar magnet is moved toward the loop, the magnetic flux in the loop 3. Therefore, the loop generates an induced B field that points the page. 4. This induced B field is due to an induced current that Sows in the loop. the 19.AO out of, increases, out of, clockwise BO into, decreases, into, clockwise CO out of, decreases, out of, clockwise DO into, increases, out of, counter-clockwise EO into, decreases, out of, counter-clockwise In the figure below, a loop is located near a long wire with current fowing as indicated. Choose the appropriate word choices below that correctly complete the blanks in the following four sentences: 1·The original B field penetrating the loop points 2. If the current in the wire increases, then the magnetic lux in the loop 3. Therefore, the loop generates an induced B field that pointsthe page. the page. I increasing in the 4. This induced B field is due to an induced current that flows loop 20.AO out of, increases, into, clockwise BO into, decreases, into, clockwise CO out of, increases, into, counter-clockwise DO out of, decreases, out of, clockwise EO into, increases, into, counter-clockwise A magnetic B feld of strength 0.4 T is perpendicular to a loop with an area of 1 m2 If the area of the loop is reduced to zero in then what is the magnitude of the induced emf voltage? (in V) X 21.AO 0 cO 0.4 DO 0.04 EO Cannot decide, need more information. A transformer has 790 primary and 80 secondary turns. An alternating potential of 50 V is applied to the primary. What is the secondary potential? (in V) 22. AO 162 BO 215 CO 286 DO 3.81 EO 5.06

Explanation / Answer

19. field lines from N to S.

So field is into the page : 1. into

2. field strength is maximum near N.

so field increases.

3. flux increases so induced field will be in opposite direction,

out of

4. B_induced = out of page so I - CCW

Ans(D)

20. 1. out of page

2. B is propotional to I so it increases.

3. flux increases so induced field will be in opposite direction.

into

4. clockwise

Ans(A)

21. e = B dA/dt = (0.4 T) (1/1) = 0.4 Volt

Ans(C)

22. Ns/ Np = Vs / Vp

80 / 790 = Vs / 50

Vs = 5.06 Volt

Ans(E)

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