6. 0/6 points| Previous Answers SerCP9 20.P.041.MI.FB. My Notes Ask Your Teacher

Question

6. 0/6 points| Previous Answers SerCP9 20.P.041.MI.FB. My Notes Ask Your Teacher A solenoid of radius 3.5 cm has 540 turns and a length of 15 cm. (a) Find its inductance You may have made an error in converting units or in keeping track of exponents. mH (b) Find the rate at which current must change through it to produce an emf of 90 mV. (Enter the magnitude.) 95.7 You may have made an error in converting units or in keeping track of exponents. A/Vs Need Help? Master lt Talk to a Tutor Submit Answer Save Progress Practice Another Version

Explanation / Answer

given, soleoid radius, r = 3.5 cm

number of turns, n = 540

length, l = 15 cm

a. inductance L

for a solenoid

L = 4*pi*k*n^2*pi*r^2/l

L = 4*pi*10^-7*540^2*pi*0.035^2/0.15

L = 0.00940139036830 H = 9.4013903683 mH

b. V = 90 mV

hence

Ldi/dt = V

di/dt = V/L = 9.5730521 A/s

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