arrangement that are either in series or parallel. We combine these as dexcribed
ID: 1731078 • Letter: A
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arrangement that are either in series or parallel. We combine these as dexcribed in Problem-Solving Strakgy 24.1 to find the nct equivalent capacitance, using .24.5 or series connections and Eq. (21.7) for parallel connections EXECUTE: The caption of Fig. 24 10 ??"lines onr prostire we, firat usc Eq. (24.5) to roplaco tho 12-?? nd €guParics combina- tius by ils equivalent capacitance C eir equivalent ig. 24.1OU) t eapacitance Cou which i our target vriable Bookmarks xport PDr EVALUATE: Ir the potential difference across the entire network in Hg. 24. iuba is Lo-vu, v, the net ctarge on the network is O-C.Nr. _ (6 ??)(9.0 V) _ 54??. Can you find the charac Adobe Export PDF > 24 CAPACITANCE ^ AND DIELECTRICS convert ??-HilQS to word RESISTANCE, AND ELECTROMOTIVE FORCE 24.10 a) A capacisoe network Detween posnts a and b. b) The 12-uand d-u capaciuors in series in (a) are replaced by an equiva- Select POF File (d) Finally, the 18 ?? and 9 ?F capacitors in series in Microsoft word ( docx) Replace thece pFreplace thoc Document Lanquagc: an oquivalent eapacitor Enylish (U.S) Chanye 20 SoURCES or MAGNETIC FIELD 29 ELECIROMAGNEFIC INDUCTION Test Yaur Understarncdinng of Section 24.2want tn monerta F capacitor and an &-paF capecitor. (a) With which type of connection will the MP Convert or series; (n) parallel: (n) eher series or parallel:() nether sernes nor parallel b) With which type of connection will the 4- capacitor have a greater charge than the S-ALT capacitor? (D series: n parallel: elther serles or parallel: av nelther series nor 30 INDUCTANCE ?Create PDF v 31 ALTERNATING CURREN 32 FI FCTROMAGNFTIC WAVES > 24.3 Energy Storage in Capacitors and Electric-Field Energy Storc and share files in the Document Cloud Learn More Many of the most important application ot capacitors depend on their ability to store energy The eleric potenrial enrey stored in a charged capacitnr is just 8.47 x 10.86 in 12:1 PM rzu18Explanation / Answer
given, the 3 uF capacitor is replaced by C
then
12uF and 6uF are in series, so replaced by 4 uF
4uF, C and 11 uF ar ein parallel
15uF + C = C'
also
Ceff = C'*9/(C' + 9) = 8
C'*9 = 8C' + 72
C' = 72
15 + C = 72
C = 57 uF
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