27.4.5 A beam of charged particles with density 35500000000000 particles/m3 is (

Question

27.4.5 A beam of charged particles with density 35500000000000 particles/m3 is (7.00) directed due east. Each particle carries a charge of +3e, and moves at a speed of 2.98x 105 m/s. (a) What are the magnitude and direction of the average curent density J of this beam? (b) You do not have enough information to calculate the current flowing in the beam. What additional information do you need? x (a) o submissions used) (2/6 submissions used) A/m2 v due east1/2 (b) The v cross-sectional area 1/2 submissions used) of the beam. Save 27.4.5 Submit 27.4.5

Explanation / Answer

(a) We know that the current density is given by
J = p*(3e)v
where p is density of particles
v is velocity
J = 355*1011*(3*1.6*10-19)*2.98*105
= 5.078 A/m2

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.