14.17 - Phase Change and Latent Heat Part A How much heat transfer is necessary

Question

14.17 - Phase Change and Latent Heat Part A How much heat transfer is necessary to raise the temperature of a 0.196-kg piece of ice from 25.0°C to 135°C, including the energy needed for phase changes? Submit Answer Tries 0/5 Part B How much time is required for each stage, assuming a constant 0.610 kJ/s rate of heat transfer? (Make a graph of temperature versus time for this process to visualize the time scale.) Ice -25.0°C to ice 0°C Ice 0°C to water 0°C Water 0°C to 100°C Water 100°C to steam 100°C Steam 100°C to 135.0°C Submit Answer Tries 0/5

Explanation / Answer

A. given m = 0.196 kg

Ti = -25 C

Tf = 135 C

Latent heat of fusion, Lf = 334,000 J/kg

Latent hea tof vapourisation, Lv = 2230,000 J/kg

Heat capacity

Ci = 2108 J/kg K

Cw = 4187 J/kg K

Cs = 1996 J/kg K

hence

total heat transfer

Q = 0.196(2108*25 + 334,000 + 4187*100 + 2230,000 + 1996*35)

Q = 608630.96 J = 608.63096kJ

B. P = 610 J/s

hence

Ice -25 C to 0 C, t1

m*Ci*dT/P = t1

t1 = 16.93311 s

Ice to water

t2 = m*Lf/P = 107.318 s

water 0 C to water 100 C

t3 = m*Cw*100/P = 134.53311 s

water to steam

t4 = mLv/P = 716.52459 s

steam 100 C to 135 C

t5 = mCs*dT/P = 22.446819672 s

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