QUESTION 1 Figure Q1 shows a concrete floor slab with an overall depth of 225 mm

Question

QUESTION 1 Figure Q1 shows a concrete floor slab with an overall depth of 225 mm and it is simply supported on pre-c KNm 2 and floor finishes of 1 0 kNm2 Calculate the ultimate design loads acting on beams ast concrete beams The slab is to be designed to carry a live load of 2 5 BM1 (grd line B1-C1), BM2 (grid line B2-C2) and BM3 (gnd line B1-B3) Using the results from above, calculate the axial design load acting on column C1 (column at grid B1) Assume the column height to be 3 0 m and the unit mass of all the beams and colu mns as 70 kg m run Nm 6 m BM2 2 Column C1 Column C:2 Figure Q1 Concrete floor slab

Explanation / Answer

given d =225 mm

b =0.5 d

b =0.5*225

b =112.5 mm

Deal load =B *D*25

=112.5*225*25

=6.32 kn/m

Live load =25 kn/m

total load =25 +6.32

=31.32 kn/m

mu =1.5 *31.32*l2/8

l =2.25 +0.25+0.25

l =2.75

Mu =1.5*31.32*2.752/8

mu=44.41 kn/m

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.