In a lab I calculated that the mass of the Earth was 1.78 x10^22 kg. The accepte

Question

In a lab I calculated that the mass of the Earth was 1.78 x10^22 kg. The accepted mass of the Earth is 5.98 x 10^24 kg. Isthis how you would find percentage error?: Absolute error = measured - accepted = 1.78 x 10^22 - 5.98 x 10^24 = -5.96 x 10^ 24kg = 5.96 x 10^24kg Percentage error = Absolute error/accepted x 100% = 5.96 x 10^24/5.98 x 10^24 x 100% = 99.7% = 100% - 99.7% = 0.3% The percentage error is 0.3% Is this the right answer? In a lab I calculated that the mass of the Earth was 1.78 x10^22 kg. The accepted mass of the Earth is 5.98 x 10^24 kg. Isthis how you would find percentage error?: Absolute error = measured - accepted = 1.78 x 10^22 - 5.98 x 10^24 = -5.96 x 10^ 24kg = 5.96 x 10^24kg Percentage error = Absolute error/accepted x 100% = 5.96 x 10^24/5.98 x 10^24 x 100% = 99.7% = 100% - 99.7% = 0.3% The percentage error is 0.3% Is this the right answer?

Explanation / Answer

Absolute error = measured - accepted = 1.78 x 10^22 - 5.98 x 10^24 = -5.96 x 10^ 24kg = 5.96 x 10^24kg Percentage error = Absolute error/accepted x 100% = 5.96 x 10^24/5.98 x 10^24 x 100% = 99.7%

answer: 99.7%

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