Okay, I am beyond completly lost. I know you have to usecertain equations to fig

Question

Okay, I am beyond completly lost. I know you have to usecertain equations to figure these out but other then that I'mcompletly clueless how to do them. If you could help that would begreat. This is worth five bonus points on my grade if I can answerall these corectly. . Your can is traveling 23.0 m/s when you see the car in frontof you slam on the breaks and stop. If you do the same but it takesyou 0.8 sec to react because your texting on your cell-phone andyou slow down at a rate of 7.6 m/s^2 to avoid hitting that car, howfar will your car go before it stops? Show all work. (Round to thetenths) . Okay, I am beyond completly lost. I know you have to usecertain equations to figure these out but other then that I'mcompletly clueless how to do them. If you could help that would begreat. This is worth five bonus points on my grade if I can answerall these corectly. . Your can is traveling 23.0 m/s when you see the car in frontof you slam on the breaks and stop. If you do the same but it takesyou 0.8 sec to react because your texting on your cell-phone andyou slow down at a rate of 7.6 m/s^2 to avoid hitting that car, howfar will your car go before it stops? Show all work. (Round to thetenths) .

Explanation / Answer

given the velocity of the car is  u = 23.0m/s reaction time is t = 0.8 sec the deceleration is a= 7.6 m/s2 the final velocity of the car is v = 0 m/s                   in the reaction time the car travells the distance S=ut = 23.0 m/s * 0.8 s = 18.4 m let the distance travelled duering decelerationis S' then we have                 v2 = u2 - 2aS'                    S' = u2 /2a = 69.6 m so the total distance travelled is = S +S'                                                 =69.6m+18.4 m                                                =88.0 m the final velocity of the car is v = 0 m/s                   in the reaction time the car travells the distance S=ut = 23.0 m/s * 0.8 s = 18.4 m let the distance travelled duering decelerationis S' then we have                 v2 = u2 - 2aS'                    S' = u2 /2a = 69.6 m so the total distance travelled is = S +S'                                                 =69.6m+18.4 m                                                =88.0 m

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