What is the initialmechanical energy (sum of the kinetic and potential energies)

Question

What is the initialmechanical energy (sum of the kinetic and potential energies)? Whatis the final mechanical energy (when the particle stops somewhereon the horizontal track)? So, how much energy is transferred tothermal energy along the horizontal track? What are the magnitudesof the normal force and the kinetic frictional force? How is theenergy lost to thermal energy related to the frictional force andthe total distance of sliding? To slide that total distance, wheredoes the particle end up?

Explanation / Answer

   = .29    by energy conservation ......    energy at A = energy at Bottom ofsideA    => M x g x h + k.e(=0) = p.e (=0) + .5 xM x V^2    => V = [2 x g x (L/2) ]       dist at which vel = 0 is ; V(f)^2 =U(i)^2 - 2 x (.29 x g) x Dist          dist = .........can be known!!    just carry out thecalculation.............

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