(a) A charge of -320 e isuniformly distributed along a circular arc of radius 4.
ID: 1733672 • Letter: #
Question
(a) A charge of -320e isuniformly distributed along a circular arc of radius 4.25 cm, which subtends an angle of 36°. What is the linearcharge density along the arc?1 C/m
(b) A charge of -320e isuniformly distributed over one face of a circular disk of radius1.95 cm. What is the surface chargedensity over that face?
2 C/m2
(c) A charge of -320e isuniformly distributed over the surface of a sphere of radius1.95 cm. What is the surface chargedensity over that surface?
3 C/m2
(d) A charge of -320e isuniformly spread through the volume of a sphere of radius1.95 cm. What is the volume charge densityin that sphere?
4C/m3
Explanation / Answer
here =360 radius r = 4.25cm charge q = -320e = -320*1.6*10-19 = -512*10-19c linear charge density = dq/ds =dq/r ( arc= - angel*radius ) = -512*10-19 1800/0.0425*360 * solve weget answer. (b) surface charge density = q/A =-512*10-19/ (0.0195)2 = -4.35*10-14 c/m2 (c) surface charge density over the spheres = q/4r2 =-520/4*3.14*(0.0195)2 solving we get =-10.90*10-15 c/m2 (d) the volume charge density v = q/4/3 r3 = -520*3/4*3.14*(0.0195)3 = - 1.6*10-12c/m3Related Questions
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