In a vacuum, two particles have charges of q 1 and q 2 , where q 1 = +3.5 µC. Th

Question

In a vacuum, two particles have charges ofq1 and q2, whereq1 = +3.5 µC. They are separated by adistance of 0.29 m, and particle 1experiences an attractive force of 2.8 N.What is q2 (magnitude and sign)? In the rectangle in the drawing, a charge is to be placed at theempty corner to make the net force on the charge at cornerA point along the vertical direction. What charge(magnitude and algebraic sign) must be placed at the empty corner?(n = 5, q = 3.9)
In a vacuum, two particles have charges ofq1 and q2, whereq1 = +3.5 µC. They are separated by adistance of 0.29 m, and particle 1experiences an attractive force of 2.8 N.What is q2 (magnitude and sign)?

Explanation / Answer

given q1 = 3.5*10-6c          r=0.29m         F = 2.8N from the columbs law F =kq1q2/r2                                 Fr2/kq1 = q2                                2.9*(0.29)2/9*109 *3.5*10-6c = q2                                  7.6*10-6 c = q2               sign is negative because there is atractive force between charges.               sign is negative because there is atractive force between charges.                                                      

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