In my book, it says that the electric field magnitude is 375N/C in the positive

Question

In my book, it says that the electric field magnitude is 375N/C in the positive x-direction and then it also wants to knowthe work done, the change in PE and the velocity of an electronthat moved 3.20 cm. Where did the numbers on the graph given come from?Thanks. In my book, it says that the electric field magnitude is 375N/C in the positive x-direction and then it also wants to knowthe work done, the change in PE and the velocity of an electronthat moved 3.20 cm. Where did the numbers on the graph given come from?Thanks.

Explanation / Answer

given distance = d = 3.20 *10-2m strength of the electric field = E = 375N/C (a) the work done by the field on the electron = W = qV= q Ed       W = (1.6*10-19 C)(375) (3.20*10-2m) = 19.2 *10-19 J (b) the change in the potential energy of the electron.               P.E = - W = - 19.2*10-19 J (c) velocity of electron v = -2/me PE                             where me is mass of electron plug values we get = v = 2.05 *106m/s and direction is negative x direction.

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