Consider two vectors with magnitude F1=98N and F2 =82N, where1 = 316 and 2=188,

Question

Consider two vectors with magnitude F1=98N and F2 =82N, where1 = 316 and 2=188, measured from the positive x- axiswith the counter-clockwise angular direction as positive. What is the magnitude of the resultant vector F,where F= FI +F2. And also find the direction of this resultant vector F asangle in drgrees, with counter-clocwise as the positive angulardirection, between the limits of -180 degrees and + 180degrees. Consider two vectors with magnitude F1=98N and F2 =82N, where1 = 316 and 2=188, measured from the positive x- axiswith the counter-clockwise angular direction as positive. What is the magnitude of the resultant vector F,where F= FI +F2. And also find the direction of this resultant vector F asangle in drgrees, with counter-clocwise as the positive angulardirection, between the limits of -180 degrees and + 180degrees.

Explanation / Answer

Phase difference between F 1 and F 2 is = 1 - 2                                                                 = 128 So, magnitude of resulatnt force F = [ F12 + F 2 2 + 2 F 1 F2 cos ] substitue values weget answer (b). Let F makes an angle with F 1 then          tan =F 2 sin / [ F 1 + F 2 cos ] subsittue values weget answer

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