A parallel-plate capacitor consist of plates of area 1.5 x10^-4 m^2 and separate

Question

A parallel-plate capacitor consist of plates of area 1.5 x10^-4 m^2 and separated by 1.0 mm. The capacitor is connectedto a 12 V battery. a. What is the capacitance? b. What is the charge on the plates? c. What is the electric field between the plates? A parallel-plate capacitor consist of plates of area 1.5 x10^-4 m^2 and separated by 1.0 mm. The capacitor is connectedto a 12 V battery. a. What is the capacitance? b. What is the charge on the plates? c. What is the electric field between the plates?

Explanation / Answer

          Giventhat the area of the each plate is A = 1.5*10-4m2          Theseparation between the two plates is d = 1.00 mm =1.00*10-3 m           Thevoltage of the battery is V = 12 V ---------------------------------------------------------------------------------------    (a)     The capacitanceis C = 0*A / d                              where  0=8.85*10-12C2N-1m-2           then weget C = --------- F     (b) The charge is q = C*V                                  = --------------- Columbs       (c) The electric field isE = V /d                                             =----------- N/C                                            Theseparation between the two plates is d = 1.00 mm =1.00*10-3 m           Thevoltage of the battery is V = 12 V ---------------------------------------------------------------------------------------    (a)     The capacitanceis C = 0*A / d                              where  0=8.85*10-12C2N-1m-2           then weget C = --------- F     (b) The charge is q = C*V                                  = --------------- Columbs       (c) The electric field isE = V /d                                             =----------- N/C                                  

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