A 1.20-m-long pipe is closed at one end. Near The open end,there is a loudspeake

Question

A 1.20-m-long pipe is closed at one end. Near The open end,there is a loudspeaker that is driven by an audio oscillator whosefrequency can be varied from 10.0 to 5000Hz (neglect any endcorrections) a) what is the lowest frequency of the oscillator that willproduce resonance within the tube? b) What is the highest frequency that will produceresonance? c) How many different frequencies of the oscillator willproduce resonance? A 1.20-m-long pipe is closed at one end. Near The open end,there is a loudspeaker that is driven by an audio oscillator whosefrequency can be varied from 10.0 to 5000Hz (neglect any endcorrections) a) what is the lowest frequency of the oscillator that willproduce resonance within the tube? b) What is the highest frequency that will produceresonance? c) How many different frequencies of the oscillator willproduce resonance?

Explanation / Answer

(a).  the lowest frequency of the oscillator thatwill produce resonance within the tube is f = v / 4L where L = length = 1.2 m            v= speed of sound = 340 m / s So, f = 70.83 Hz (b). the highest frequency that will produce resonance n =5000 / f                                                                                     =70.58 So, answer is   N f where N = 70

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