An automobile starts from rest and accelerates to a finalvelocity in two stages

Question

An automobile starts from rest and accelerates to a finalvelocity in two stages along a straight road. Each stage occupiesthe same amount of time. In stage 1, the magnitude of the car'sacceleration is 3.3 m/s2. Themagnitude of the car's velocity at the end of stage 2 is2.1 times greater than it is at the end ofstage 1. Find the magnitude of the acceleration in stage2.
An automobile starts from rest and accelerates to a finalvelocity in two stages along a straight road. Each stage occupiesthe same amount of time. In stage 1, the magnitude of the car'sacceleration is 3.3 m/s2. Themagnitude of the car's velocity at the end of stage 2 is2.1 times greater than it is at the end ofstage 1. Find the magnitude of the acceleration in stage2.

Explanation / Answer

stage one: v1 = a1*t1. (v1 is the velocity at the end of stage 1) stage two: v2 = v1 + a2*t2 (v2 is the velocity at the end of stage 2) v2 = 2.1v1 sub in 2.1v1 for v2 and then a1*t1 for v1 and you get this equationto solve for a2. 2.1a1*t = a1*t +a2 *t (t1 and t2 are equal. just t now) divide t out. 2.1a1 = a1 + a2 2.1*3.3 = 3.3 + a2 a2 = 3.63m/s^2

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