first segment 1 ft/s second segment 2 Your answer differs from the correct answe

Question

first segment 1 ft/s second segment 2
Your answer differs from the correct answerby 10% to 100%. ft/s third segment 3
Your answer differs from the correct answerby 10% to 100%. ft/s fourth segment 4
Your answer differs from the correct answerby 10% to 100%. ft/s fifth segment 5
Your answer differs from the correct answerby 10% to 100%. ft/s

Explanation / Answer

1mile = 5280ft 1st segment: (.25mile)/(24.9s)= 0.01mile/sec to get ft/s you need to multiply by 5280ft => Vavg = 53.01ft/s For the rest of the segments you're doing the initial math right,but you cannot add average speeds to get a total average speed. Sothe Vavg1 + Vavg2 is NOT Vavg1-2. Also the problem is only askingyou for the average speed for each segment, so you don't have toworry about previous averages when considering a segment's avgvelocity. For part B just use whatever value you get for Vavg5 as you Vf, Viis 0 because the Secretariat started from rest, and t is the totaltime to complete 1.25 miles. Then you could solve for theacceleration.

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