I cannot figure out how the set up this problem: A rock is dropped from a sea cl

Question

I cannot figure out how the set up this problem: A rock is dropped from a sea cliff and thesound of it striking the ocean is heard 6.5 seconds later. Ifthe spee of sound is 340 m/s, how high is thecliff? I know that the times must be subtracted and I know thatthe time for return sound is H/340m/s. What is the time to be usedin the free fall part in order to calculate the height of thecliff? This is from an online homework assignment. I cannot figure out how the set up this problem: A rock is dropped from a sea cliff and thesound of it striking the ocean is heard 6.5 seconds later. Ifthe spee of sound is 340 m/s, how high is thecliff? I know that the times must be subtracted and I know thatthe time for return sound is H/340m/s. What is the time to be usedin the free fall part in order to calculate the height of thecliff? This is from an online homework assignment.

Explanation / Answer

g=accleration due to gravity=9.8 let the cliff is H m high to travel H m sound took H/340 s in 6.5-(H/340) s the rock fell H m H=u*t+(1/2)*g*t2 H=0+(1/2)*9.8*[6.5-(H/340)]2(H/4.9)=[6.5-(H/340)]2 from the above equation we have to find out H which is the cliffheight after we get the H . we can calculate free fall time by using[6.5-(H/340)]

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